PART I – Free Response

 

Directions:  COMPLETE THE TABLES BELOW.  Write clearly or your answer is VOID.   Show all work in the space provided or your answer is VOID!!  Remember to record the units. 

Table I – Significant Figures and Dimensional Analysis

Problem

Show work in space provided in this section.

Answer in Scientific Notation

 

(7.560 x 103 + 2.10 x 101)

                         9.107

7.560 x 103  +  0.0210 x 103  =  7.5810 x 103 

 

7.5810 x 103  /  9.107  =  832.44 

8.324 x 102

 

10.3 x 10¯5  –  10.3 x 10¯4

 

 

10.3 x 10¯5   -   103  x 10¯5  =  –9.27 x 10¯4

 

– 9.3 x 10¯4

 

Table II – Dimensional Analysis                

Problem

Show work in space provided in this section.

Answer in Scientific Notation

 

How many kiloliters are in

9.58 x 109 cubic dekameters?

 

 

?kL = 9.58 x 109 dam3    x     1 x 109cm3    x    1 mL       x    1 kL             

                                                   1 dam3            1 cm3         1 x 106mL

      = 9.58 x 1013kL

 

   9.58 x 1013kL

9.2 cm  X  6.00 hm  X  0. 0530 m

Place answer in dam3.

 

(9.2 cm x  1 dam    ) ( 6.00 hm   x  1 x 101 dam) (0.0530 m x 1 dam  )

                  1 x 103cm                            1 hm                                1 x 101m

 

=0.0029256 dam3

  2.9 x 10-3 dam3

How many GL of air fill a room that is

200 dm in width, 1.50 km in length and 0.6400 hm in height? (SEE Volume BELOW)

? GL  =  1.92 x 1o12cm3   x   1 mL   x   1  GL         =   2  GL

                                    1 cm3      1 x 1012

 

   2  x 100 GL

Volume = (200 dm x 1 x 101cm)   (1.50 km  x  1 x 105cm)   (0.6400 hm  x   1 x 104cm)   =  1.92 x 1012cm3

1 dm                                    1 km                                            1 hm