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Quiz Key
(Chem. 10)

Summer  2008

 

 

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Quiz I

1. Get the conversion factor for the unit of surface area from 1 mm = 10-6 m

(1 mm)2 = (10-6 m)2

1 mm2 = (10-12 m2

2. Write the conversion ratios for the 1 lb = 453.6 g conversion factor

1 lb / 453.6 g ,         453.6 g / 1 lb

3. Convert 1.23 x 1022 pm3 to in3 .

1.23 x 1022 pm3  x ( 10-12 m / 1pm)3 x ( 1 cm / 10-2 m )3 x ( 1 in / 2.54 cm)3 = 7.5 x 10-8 in3

4. A solid sample has the density of 11.22 g/ ml. and mass of 8.902 g. Calculate volume off the solid sample.

8.902 g x ( 1 ml. / 11.22 g) = 0.7934 ml.

5. Convert 112.5 o F to o C.

o F = 1.8 x o C + 32

o C =( o F - 32) / 1.8

o C = (112.5  o F - 320 / 1.8

44.7 o C

6. Which of the following substances is element/ compound?

a. CO : compound

b. B2O3 : compound

c. Fe : element

Quiz II

1. Complete the following table:

Symbol

Z

A

P+

e-

no

K

19

39

19

19

20

Cl

17

35

17

17

20

Se

34

74

34

34

40

 

2. Find name and symbol of an atom in period 3 and VIA group.

Sulfur, S

 

3. An atom has the atomic number of 42, find the period and group.

Period 5, B (transition group)

4. Complete the following table:

Name

Symbol

argon

Ar

nitrogen

N

Quiz III

1. Write the formula of each of the following compounds:

a. chromium (III) sulfate:  Cr2(SO4)3

b. potassium iodide: KI

c. diphosphorus trioxide: P2O3

d. chlorous acid: HClO2 (aq)

2. Write the Stock-system name of the following compounds:

a. FeO : iron (II) oxide

b. Al(HCO3)3: aluminum hydrogen carbonate

c. SiO2: silicon dioxide

d. HI(aq): hydroiodic acid

3. A compound has 59.63%Cl and 40.4% O. Calculate the empirical formula.

moles of Cl: 59.63 g Cl x (1mole Cl / 35.45 g Cl) = 1.682

moles of O : 40.4 g O x ( 1mole O / 16.00 g O) = 2.53

1.682 moles Cl / 1.682 = 1.000 moles Cl

2.53 moles O / 1.682 = 1.50 moles O

1.000 moles Cl x 2 = 2.000 moles Cl

1.50 moles O x 2 = 3.00 moles O

empirical formula:  Cl2O3

4. Balance the following chemical equation:

2Cr(s) + 6HCl (aq) ------- > 2CrCl3 (aq) + 3H2 (g)

5. Identify the type of the following chemical reaction:

H2SO3(aq) ---------- > SO (g) + H2O      decomposition reaction

Quiz IV:

1.  Consider the following chemical reaction:

CaC2(s) + 2H2O --------- > Ca(OH)2 (s) + C2H2 (g)

11.2 g CaC2 react with excess of water, calculate the theoretical yield of C2H2.

11.2 g CaC2 x ( 1mole / 64.10 g CaC2) x (1mole C2H2/ 1mole CaC2) x (26.04 g C2H2 / 1 mole C2H2) = 4.55 g C2H2

2. Refer to problem #1 if 1.340 g C2H2 have been recovered, calculate the %yield.

%yield = (1.340 g C2H2 / 4.55 g C2H2) x 100 = 29.5%

3. 44.67 g iron absorbs 266 J of heat and its temperature is increased by 23.0 oC. calculate the specific heat of iron.

Q = m x s x Dt

Dt = t2 - t1

s = Q / ( m Dt )

s = 266 J / ( 44.67 g x 23.0 oC)

s = 0.260 J / g oC

4. Write the complete electronic configuration of an atom having atomic number of 22.

1s2, 2s2, 2p6, 3s2, 3p6, 4s2, 3d2

5. Refer to problem number 4 is the atom in the main group or transition group?

transition group

Quiz V:

1. Draw the Lewis structure of COCl2:

                          : O :

                     ..     | |    ..

                  :  Cl - C - Cl :

                     ..           ..

2. Determine the molecular shape of COCl2:

trigonal planar

3. A sample of gas has the volume of 33.4 L. with the pressure of 3.45 atm. at 22 oC. Calculate the volume at STP

P1V1 / T1 = P2V2 / T2

V2 = P1V1T2 / T1P2

T1 = 11 oC + 273 = 295 K

T2 = 0 oC + 273 = 273 K

V2 = (3.45 atm. x 33.4 L. x 295 K) / (273 K x 1.00 atm.)

V2 = 107 L.

4. Consider the following chemical reaction:

N2 (g) + 3H2 (g) ------ > 2NH3 (g)

1.70 g ammonia gas has been obtained. Calculate volume of of H2(g) at 25 oC and pressure of 11.4 atm.

g of NH3 ----------------- > moles of NH3 -------------- > moles of H2

1.70 g NH3 x (1mole NH3 / 17.02 g NH3) x ( 3 moles H2 / 2 moles NH3) = 0.150 moles H2

PV = nRT

V = nRT / P

T = 25 oC + 273 = 298 K

V = (0.150 moles x 0.0821 atm. L. mole -1 K-1 x 298 K) / 11.4 atm.

V = 0.322 L.

5. Calculate the amount of heat to vaporize 10.2 g water at its boiling point.

10. g H2O x ( 1mole H2O / 18.02 g H2O) x (40.7 kJ / 1 mole H2O) = 23.0 kJ

 

 

      

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

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Last Update:  July 17, 2008